Explain why the following doesn't work as an IIFE: `function foo(){}();`. What needs to be changed to properly make it an IIFE?
TL;DR
The code function foo(){}(); doesn't work as an Immediately Invoked Function Expression (IIFE) because the JavaScript parser treats function foo(){} as a function declaration, not an expression. To make it an IIFE, you need to wrap the function in parentheses to turn it into a function expression: (function foo(){})();.
Why the code doesn't work as an IIFE
Function declaration vs. function expression
In JavaScript, a function declaration and a function expression are treated differently by the parser. The code function foo(){} is interpreted as a function declaration. Function declarations are not immediately invoked; they are hoisted to the top of their scope and can be called later in the code.
Syntax error
When you try to immediately invoke a function declaration by adding (); at the end, it results in a syntax error because the parser expects a function expression to be invoked immediately, not a declaration.
How to properly make it an IIFE
Wrapping in parentheses
To convert the function declaration into a function expression, you need to wrap the function declaration in parentheses. This tells the JavaScript parser to treat it as an expression. Here is the corrected code:
Alternative syntax
You can also use an alternative syntax by placing the parentheses around the original line:
Both of these syntaxes are valid and will correctly create an IIFE.